5x^2=216

Solution for 5x^2=216 equation:

5x^2=216

We move all terms to the left:

5x^2-(216)=0

a = 5; b = 0; c = -216;
Δ = b2-4ac
Δ = 02-4·5·(-216)
Δ = 4320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4320}=\sqrt{144*30}=\sqrt{144}*\sqrt{30}=12\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{30}}{2*5}=\frac{0-12\sqrt{30}}{10}
=-\frac{12\sqrt{30}}{10}
=-\frac{6\sqrt{30}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{30}}{2*5}=\frac{0+12\sqrt{30}}{10}
=\frac{12\sqrt{30}}{10}
=\frac{6\sqrt{30}}{5}
$